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-.015d^2+1.8d+2=0
We add all the numbers together, and all the variables
-0.015d^2+1.8d+2=0
a = -0.015; b = 1.8; c = +2;
Δ = b2-4ac
Δ = 1.82-4·(-0.015)·2
Δ = 3.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.8)-\sqrt{3.36}}{2*-0.015}=\frac{-1.8-\sqrt{3.36}}{-0.03} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.8)+\sqrt{3.36}}{2*-0.015}=\frac{-1.8+\sqrt{3.36}}{-0.03} $
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